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UNIT SYLLABUS

A.4 Rigid body mechanics

HL 7 hours · HL only
Everything you learned about linear motion has a rotational twin, and this HL unit introduces the full dictionary: force becomes torque, mass becomes moment of inertia, momentum becomes angular momentum, and Newton's second law becomes $\tau = I\alpha$. The deep new idea is that how mass is distributed matters as much as how much there is — a hollow cylinder is harder to spin than a solid one of equal mass. Conservation of angular momentum explains why an ice skater spins faster when pulling in their arms, why neutron stars rotate hundreds of times a second, and why helicopters need tail rotors.

Guiding Questions

  • ? How is the rotational motion of a rigid body analogous to the translational motion of a point mass?
  • ? What quantities are conserved in rotational dynamics, and under what conditions?

What the IB expects you to master

  • Calculate the torque of a force about an axis: τ=Frsinθ\tau = Fr\sin\theta.
  • Apply the conditions for rotational equilibrium (resultant torque zero) and recognise that an unbalanced torque produces angular acceleration.
  • Use the rotational suvat equations for uniform angular acceleration (ωf=ωi+αt\omega_f = \omega_i + \alpha t, Δθ=ωit+12αt2\Delta\theta = \omega_i t + \frac{1}{2}\alpha t^2, ωf2=ωi2+2αΔθ\omega_f^2 = \omega_i^2 + 2\alpha\Delta\theta).
  • Explain how moment of inertia depends on the distribution of mass about the axis, and compute I=Σmr2I = \Sigma mr^2 for point-mass systems.
  • Apply Newton's second law for rotation, τ=Iα\tau = I\alpha.
  • Use angular momentum L=IωL = I\omega, its conservation in the absence of external torque, and angular impulse ΔL=τΔt\Delta L = \tau\Delta t.
  • Calculate rotational kinetic energy Ek=12Iω2E_k = \frac{1}{2}I\omega^2, including bodies that roll (translation + rotation).

1 Key Formulas

Torque
τ=Frsinθ\tau = Fr\sin\theta
Rotational second law
τ=Iα\tau = I\alpha
Moment of inertia (point masses)
I=Σmr2I = \Sigma mr^{2}
Rotational kinematics
ωf=ωi+αt\omega_{f} = \omega_{i} + \alpha t
Angular displacement
Δθ=ωit+12αt2\Delta\theta = \omega_{i}t + \tfrac{1}{2}\alpha t^{2}
Angular velocity–displacement
ωf2=ωi2+2αΔθ\omega_{f}^{2} = \omega_{i}^{2} + 2\alpha\Delta\theta
Angular momentum
L=IωL = I\omega
Angular impulse
ΔL=τΔt\Delta L = \tau\Delta t
Rotational kinetic energy
Ek=12Iω2=L22IE_{k} = \tfrac{1}{2}I\omega^{2} = \frac{L^{2}}{2I}

2 Exam Preparation & Topic Explanations

The linear–rotational dictionary

Almost every rotational problem is a linear problem you already know, translated word for word. Build the dictionary until it is reflexive: sθs \to \theta, vωv \to \omega, aαa \to \alpha, mIm \to I, FτF \to \tau, pLp \to L.

For rolling bodies, total kinetic energy is 12mv2+12Iω2\frac{1}{2}mv^2 + \frac{1}{2}I\omega^2 with v=ωrv = \omega r — energy conservation with both terms is the standard hard question.

Pro Exam Strategy
  • Torque depends on where the force acts: τ=Frsinθ\tau = Fr\sin\theta uses the perpendicular distance from the axis.

  • Conservation of angular momentum questions signal themselves with "no external torque" — skaters, collapsing stars, merging discs.

  • Moments of inertia for standard shapes are given in exams; only I=Σmr2I = \Sigma mr^2 for point masses must be computed from scratch.

  • When something rolls without slipping, friction does no work — mechanical energy is still conserved.

3 MCQ Practice

Q1. An ice skater spinning with arms outstretched pulls her arms in. Which row is correct?

  • Angular momentum increases; kinetic energy constant
  • Angular momentum constant; kinetic energy increases
  • Both angular momentum and kinetic energy constant
  • Angular momentum constant; kinetic energy decreases

Q2. Two children of equal mass sit on a seesaw, one at 2.0 m and one at 1.5 m from the pivot. For balance, an extra downward force must act on the shorter side. If each child weighs 400 N, what extra torque is needed?

  • 100 N m100\ \text{N m}
  • 200 N m200\ \text{N m}
  • 400 N m400\ \text{N m}
  • 800 N m800\ \text{N m}

Q3. A solid sphere and a hollow sphere of equal mass and radius roll from rest down the same incline. Which reaches the bottom first?

  • The solid sphere
  • The hollow sphere
  • They arrive together
  • It depends on the angle of the incline

4 Short Answer Questions

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