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UNIT SYLLABUS

A.3 Work, energy and power

SL/HL 8 hours
Energy is physics' universal currency, and this unit teaches you the accounting rules. Work is the mechanism that transfers energy ($W = Fs\cos\theta$ — only the force component along the motion counts). Mechanical energy comes in three interchangeable forms — kinetic, gravitational potential and elastic potential — and when resistive forces are absent, their total is conserved. Energy methods often crack problems that would be miserable with forces alone: no vectors, no components, just a before-and-after balance sheet. Power and efficiency then connect the physics to engines, motors and the real-world cost of wasted energy.

Guiding Questions

  • ? How are concepts of work, energy and power used to predict changes within a system?
  • ? How can a consideration of energy transfers simplify problems that forces make difficult?

What the IB expects you to master

  • Apply the principle of conservation of energy and represent energy transfers on a Sankey diagram.
  • Calculate work done by a constant force as W=FscosθW = Fs\cos\theta and interpret work as energy transferred.
  • Recognise that the work done by the resultant force equals the change in the system's energy.
  • Use the three forms of mechanical energy: Ek=12mv2=p22mE_k = \frac{1}{2}mv^2 = \frac{p^2}{2m}, ΔEp=mgΔh\Delta E_p = mg\Delta h, and EH=12k(Δx)2E_H = \frac{1}{2}k(\Delta x)^2.
  • Apply conservation of mechanical energy when friction and resistance are absent, and account for the energy dissipated when they are not.
  • Calculate power as P=ΔW/Δt=FvP = \Delta W/\Delta t = Fv and efficiency as useful output over total input (energy or power).
  • Compare fuel sources by their energy density.

1 Key Formulas

Work done
W=FscosθW = Fs\cos\theta
Kinetic energy
Ek=12mv2=p22mE_{k} = \tfrac{1}{2}mv^{2} = \frac{p^{2}}{2m}
Gravitational PE (near surface)
ΔEp=mgΔh\Delta E_{p} = mg\Delta h
Elastic potential energy
EH=12k(Δx)2E_{H} = \tfrac{1}{2}k(\Delta x)^{2}
Power
P=ΔWΔt=FvP = \frac{\Delta W}{\Delta t} = Fv
Efficiency
η=EoutputEinput=PoutputPinput\eta = \frac{E_{\text{output}}}{E_{\text{input}}} = \frac{P_{\text{output}}}{P_{\text{input}}}

2 Exam Preparation & Topic Explanations

Choosing energy methods over forces

When a question involves speeds at two positions and the path between them is curved or complicated, energy conservation is almost always the intended route: kinematics equations only work for constant acceleration along a straight line.

Write a clear energy balance: initial mechanical energy = final mechanical energy + energy dissipated. That single line often scores method marks even if arithmetic slips.

Pro Exam Strategy
  • Work–energy problems don't care about the path when only gravity acts — height change is everything.

  • P=FvP = Fv is the fastest route for constant-speed problems: driving force equals resistance.

  • Watch for the word "smooth" (no friction — mechanical energy conserved) versus "rough" (include dissipation).

  • Energy density questions compare fuels: energy per kilogram or per cubic metre, a favourite for data-response questions.

3 MCQ Practice

Q1. A porter carries a heavy suitcase horizontally at constant velocity across a level floor. The work done on the suitcase by the supporting force is:

  • Positive
  • Negative
  • Zero
  • Cannot be determined

Q2. A pendulum bob is released from a height hh above its lowest point. Ignoring air resistance, its speed at the lowest point is:

  • gh\sqrt{gh}
  • 2gh\sqrt{2gh}
  • 2gh2\sqrt{gh}
  • ghgh

Q3. A motor rated at 1.5 kW raises a 60 kg load at a steady 2.0 m s12.0\ \text{m s}^{-1}. What is the efficiency of the system?

  • 58%
  • 66%
  • 78%
  • 92%

4 Short Answer Questions

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