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UNIT SYLLABUS

F.2 Forces and Hooke's Law

SL
Investigating Newton's laws of motion, contact vs non-contact forces, friction, and the elastic stretching of springs.

1 Key Formulas

Hooke's Law (restoring force)
F=kxF = -kx
Newton's Second Law
Fnet=maF_{net} = ma

2 Exam Preparation & Topic Explanations

Hooke’s Law Investigations & Graphs

Hooke’s law is a core practical. Exam questions often show a force–extension graph and ask you to:

- Determine the spring constant kk from the gradient.

- Identify the limit of proportionality (point where graph stops being a straight line).

- Explain that beyond the elastic limit the spring is permanently deformed.

Key formula: F=kxF = kx (when using applied force) – the gradient of a force–extension graph gives kk.

MYP command terms used:

- *Determine*: Find the value, often from a graph.

- *Explain*: “The spring obeys Hooke’s law until the extension reaches X cm because the graph is a straight line through the origin.”

Pro Exam Strategy
  • Always convert extension to meters.

  • When calculating kk from a graph, select two points far apart on the straight section.

  • Many past questions ask: ‘Why does the spring not return to its original length after a large force?’ – Answer: it has exceeded its elastic limit and undergone plastic deformation.

Resultant Forces and Equilibrium

Newton’s First Law: An object remains at rest or in uniform motion unless acted on by a resultant force.

Free‑body diagrams are a frequent exam task. Arrows represent forces; their length indicates magnitude.

If an object is stationary or moving at constant speed, forces are balanced → resultant force = 0.

Calculation: Fnet=maF_{net} = ma, where FnetF_{net} is the resultant force. If mass is in kg and acceleration in m/s², force is in newtons (N).

Pro Exam Strategy
  • Draw free‑body diagrams with arrows touching the object, labelled clearly.

  • Never include ‘centrifugal force’ – it doesn’t exist in MYP.

  • If an object accelerates, the resultant force is in the direction of acceleration.

3 MCQ Practice

Q1. A spring with a constant of 50 N/m is stretched by 0.1 meters. What restoring force is exerted by the spring?

  • 5N5\, N
  • 50N50\, N
  • 500N500\, N
  • 0.2N0.2\, N

Q2. Which of the following is a non-contact force?

  • Frictional force
  • Tension
  • Air resistance
  • Gravitational force

4 Short Answer Questions

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