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MYP Physics

F.2 Forces and Hooke's Law

Investigating Newton's laws of motion, contact vs non-contact forces, friction, and the elastic stretching of springs.

Questions to explore

  • ? Why do objects change their motion — or refuse to?
  • ? How far can we stretch a material before it stops springing back?

💡 Key ideas, explained simply

🤝 Contact vs non-contact forces

Contact forces need objects to touch: friction, tension in a rope, the normal (support) force, air resistance.

Non-contact forces act across a gap through a *field*: gravity, magnetism, and electrostatic force. A dropped ball falls because Earth pulls it with gravity — nothing has to touch it.

🪢 Balanced vs unbalanced forces

When forces are balanced (resultant = 00) an object stays still or keeps moving at constant velocity — that is Newton's first law.

When forces are unbalanced, the object accelerates in the direction of the resultant force, following Fnet=maF_{net} = ma. Bigger resultant force → bigger acceleration; more mass → smaller acceleration.

🔗 Hooke's law and springs

Pull a spring and it stretches; the extension is proportional to the force — double the force, double the stretch. This is Hooke's law, F=kxF = kx, where kk is the spring constant (stiffness).

But only up to the elastic limit. Stretch it too far and it deforms permanently and never returns to its original length.

📖 Key terms

Force
A push or pull, measured in newtons (N).
Resultant force
The single force equal to all forces added together (with direction).
Free-body diagram
A sketch showing every force acting on one object as labelled arrows.
Spring constant kk
How stiff a spring is, in N/m — the gradient of a force–extension graph.
Elastic limit
The point beyond which a spring is permanently deformed.
Friction
A contact force that opposes motion between surfaces.

1 Key Formulas

Hooke's Law (restoring force)
F=kxF = -kx
Newton's Second Law
Fnet=maF_{net} = ma

✏️ Worked example

Use Hooke's law

A spring has a spring constant k=40 N/mk = 40\text{ N/m}. What force is needed to stretch it by 0.15 m0.15\text{ m}?

  1. 1

    Write the formula

    F=kxF = kx

  2. 2

    List the values

    k=40 N/mk = 40\text{ N/m}, extension x=0.15 mx = 0.15\text{ m}.

  3. 3

    Substitute

    F=40×0.15F = 40 \times 0.15

F = 6 N — and this only holds while the spring is below its elastic limit.

🛏️ Physics around you

Bathroom scales, mattress springs, and the suspension in a car all use Hooke's law. A weighing machine turns the stretch (or squash) of a spring into a reading, because the compression is proportional to your weight.

🎯 Nail it in the exam

Hooke’s Law Investigations & Graphs

Hooke’s law is a core practical. Exam questions often show a force–extension graph and ask you to:

- Determine the spring constant kk from the gradient.

- Identify the limit of proportionality (point where graph stops being a straight line).

- Explain that beyond the elastic limit the spring is permanently deformed.

Key formula: F=kxF = kx (when using applied force) – the gradient of a force–extension graph gives kk.

MYP command terms used:

- *Determine*: Find the value, often from a graph.

- *Explain*: “The spring obeys Hooke’s law until the extension reaches X cm because the graph is a straight line through the origin.”

Pro Exam Strategy
  • Always convert extension to meters.

  • When calculating kk from a graph, select two points far apart on the straight section.

  • Many past questions ask: ‘Why does the spring not return to its original length after a large force?’ – Answer: it has exceeded its elastic limit and undergone plastic deformation.

Resultant Forces and Equilibrium

Newton’s First Law: An object remains at rest or in uniform motion unless acted on by a resultant force.

Free‑body diagrams are a frequent exam task. Arrows represent forces; their length indicates magnitude.

If an object is stationary or moving at constant speed, forces are balanced → resultant force = 0.

Calculation: Fnet=maF_{net} = ma, where FnetF_{net} is the resultant force. If mass is in kg and acceleration in m/s², force is in newtons (N).

Pro Exam Strategy
  • Draw free‑body diagrams with arrows touching the object, labelled clearly.

  • Never include ‘centrifugal force’ – it doesn’t exist in MYP.

  • If an object accelerates, the resultant force is in the direction of acceleration.

🧠 Check your understanding

Tap an answer to see if you're right — and why.

Q1. A spring with a constant of 50 N/m is stretched by 0.1 meters. What restoring force is exerted by the spring?

  • 5N5\, N
  • 50N50\, N
  • 500N500\, N
  • 0.2N0.2\, N

Q2. Which of the following is a non-contact force?

  • Frictional force
  • Tension
  • Air resistance
  • Gravitational force

📝 Exam-style questions

Try each one, then reveal the model answer.

PDF

Download the practice worksheet

All questions from this topic + answer key — free, printable.

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