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UNIT SYLLABUS

B.3 Gas laws

SL/HL 6 hours
The ideal gas is physics' most successful simplification: model molecules as point particles in random motion with no interactions except collisions, and the messy behaviour of $10^{23}$ particles collapses into one clean equation, $PV = nRT$. This unit connects the macroscopic (pressure, volume, temperature — the empirical gas laws) to the microscopic (kinetic theory, where pressure comes from molecular impacts and $P = \frac{1}{3}\rho v^2$). You will also learn when the model breaks: at high pressures and low temperatures, real molecules' size and mutual attractions start to matter.

Guiding Questions

  • ? How does the motion of molecules explain the macroscopic properties of a gas?
  • ? Under what conditions does the ideal gas model approximate real gases well?
V P T₁ T₂ T₃ > T₂ > T₁ each curve: PV = nRT (T fixed)
Isotherms of an ideal gas on a p–V diagram: each curve shows PV = constant at one temperature, with higher temperatures lying further from the origin.

What the IB expects you to master

  • Define pressure as P=F/AP = F/A for a force perpendicular to a surface.
  • Use the amount of substance n=N/NAn = N/N_A.
  • Describe the ideal gas as a model system built from kinetic theory assumptions, used to approximate real gases.
  • Derive and use the empirical laws (constant PP, VV or TT) combined as PVT=constant\frac{PV}{T} = \text{constant}.
  • Apply the ideal gas equations PV=NkBTPV = Nk_BT and PV=nRTPV = nRT.
  • Explain pressure microscopically — molecular momentum changes at the walls — leading to P=13ρv2P = \frac{1}{3}\rho v^2.
  • Relate internal energy of an ideal monatomic gas to temperature: U=32NkBT=32nRTU = \frac{3}{2}Nk_BT = \frac{3}{2}nRT.
  • State the conditions (low pressure, low density, moderate temperature) under which real gases behave ideally.

1 Key Formulas

Pressure
P=FAP = \frac{F}{A}
Amount of substance
n=NNAn = \frac{N}{N_{A}}
Ideal gas law
PV=nRT=NkBTPV = nRT = Nk_{B}T
Combined gas law
P1V1T1=P2V2T2\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}
Pressure (kinetic theory)
P=13ρv2P = \tfrac{1}{3}\rho v^{2}
Internal energy (monatomic)
U=32NkBT=32nRTU = \tfrac{3}{2}Nk_{B}T = \tfrac{3}{2}nRT

2 Exam Preparation & Topic Explanations

Gas law problem technique

Before any algebra: convert temperatures to kelvin, decide what stays constant, and choose between the two-state form (P1V1/T1=P2V2/T2P_1V_1/T_1 = P_2V_2/T_2) and the single-state form (PV=nRTPV = nRT). Two-state problems never need RR; single-state problems usually do.

Graph literacy scores marks: isotherms on a p–V diagram, straight lines through the origin for PPTT and VVTT (kelvin only), and what "further from origin" means for temperature.

Pro Exam Strategy
  • Kelvin, always. A single Celsius slip invalidates the whole calculation.

  • The mass of gas is fixed unless the question says otherwise — a leaking container changes nn.

  • P=13ρv2P = \frac{1}{3}\rho v^2 uses the mean square speed; take a square root at the end for vrmsv_{rms}.

  • Extrapolating VVTT lines to zero volume locates absolute zero — a classic data-analysis question.

3 MCQ Practice

Q1. A fixed mass of ideal gas is heated at constant volume. Its pressure rises because the molecules:

  • Expand and take up more space
  • Collide with the walls more often and with greater momentum change
  • Repel each other more strongly
  • Increase in mass

Q2. An ideal gas at 27 °C is heated at constant pressure until its volume doubles. Its new temperature is:

  • 54 °C
  • 600 K
  • 327 °C
  • 150 K

Q3. A real gas behaves most like an ideal gas at:

  • High pressure and low temperature
  • High pressure and high temperature
  • Low pressure and high temperature
  • Low pressure and low temperature

4 Short Answer Questions

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