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UNIT SYLLABUS

B.1 Thermal energy transfers

SL/HL 6 hours
Heat is energy on the move, and this unit explains both why it moves and how fast. The molecular picture comes first: temperature in kelvin measures the average kinetic energy of particles ($\bar{E}_k = \frac{3}{2}k_BT$), while internal energy adds up all the random kinetic energy plus the potential energy stored in intermolecular bonds. That picture explains phase changes (energy rearranges bonds at constant temperature) and the workhorse equations $Q = mc\Delta T$ and $Q = mL$. Then come the three transfer mechanisms — conduction, convection and radiation — with the Stefan–Boltzmann and Wien laws powerful enough to take the temperature of a star from its light alone.

Guiding Questions

  • ? How do macroscopic observations of temperature relate to the microscopic behaviour of particles?
  • ? How is thermal energy transferred within and between systems?

What the IB expects you to master

  • Describe solids, liquids and gases with molecular theory, and use density ρ=m/V\rho = m/V.
  • Convert between Kelvin and Celsius scales, noting that temperature differences are identical in both.
  • Interpret absolute temperature as a measure of average particle kinetic energy: Eˉk=32kBT\bar{E}_k = \frac{3}{2}k_B T.
  • Define internal energy as total intermolecular potential energy plus total random kinetic energy of the molecules.
  • Explain that thermal energy flows from higher to lower temperature, and that phase changes occur at constant temperature.
  • Calculate thermal energy transfers with Q=mcΔTQ = mc\Delta T (specific heat capacity) and Q=mLQ = mL (specific latent heat of fusion or vaporization).
  • Compare conduction (particle collisions), convection (fluid density differences) and radiation (electromagnetic waves).
  • Use the conduction rate equation ΔQΔt=kAΔTΔx\frac{\Delta Q}{\Delta t} = kA\frac{\Delta T}{\Delta x}.
  • Apply the Stefan–Boltzmann law L=σAT4L = \sigma A T^4, apparent brightness b=L4πd2b = \frac{L}{4\pi d^2}, and Wien's law λmaxT=2.9×103 m K\lambda_{max}T = 2.9\times10^{-3}\ \text{m K} to blackbody radiators including stars.

1 Key Formulas

Density
ρ=mV\rho = \frac{m}{V}
Average particle KE
Eˉk=32kBT\bar{E}_{k} = \tfrac{3}{2}k_{B}T
Specific heat capacity
Q=mcΔTQ = mc\Delta T
Latent heat
Q=mLQ = mL
Conduction rate
ΔQΔt=kAΔTΔx\frac{\Delta Q}{\Delta t} = kA\frac{\Delta T}{\Delta x}
Stefan–Boltzmann law
L=σAT4L = \sigma A T^{4}
Apparent brightness
b=L4πd2b = \frac{L}{4\pi d^{2}}
Wien's displacement law
λmaxT=2.9×103 m K\lambda_{\text{max}} T = 2.9 \times 10^{-3}\ \text{m K}

2 Exam Preparation & Topic Explanations

Mixture problems without tears

Calorimetry questions reduce to one statement: energy lost by hot = energy gained by cold. Write each term as mcΔTmc\Delta T or mLmL, keep every ΔT\Delta T positive by thinking physically about direction, and solve.

When phase changes are involved, check whether there is enough energy to complete the change before assuming a final temperature — as in ice-and-water problems, the answer may sit exactly at the phase-change temperature.

Pro Exam Strategy
  • Latent heat questions: no ΔT\Delta T term during the phase change itself.

  • Kelvin is compulsory in Eˉk=32kBT\bar{E}_k = \frac{3}{2}k_BT and all radiation laws.

  • Stefan–Boltzmann uses surface area: 4πR24\pi R^2 for a sphere — forgetting the 4 is the classic slip.

  • Apparent brightness vs luminosity: luminosity is intrinsic power; brightness is what reaches you, diluted by 4πd24\pi d^2.

3 MCQ Practice

Q1. Ice at 0 °C melts to water at 0 °C. During melting, the thermal energy supplied goes to:

  • Increasing the average kinetic energy of the molecules
  • Increasing the potential energy of the molecules
  • Increasing both kinetic and potential energy equally
  • Increasing the temperature of the water

Q2. Star X has twice the surface temperature and half the radius of star Y. The ratio of luminosities LX/LYL_X/L_Y is:

  • 1
  • 2
  • 4
  • 8

Q3. A metal spoon and a wooden spoon are both at room temperature. The metal one feels colder because:

  • Metal is at a lower temperature
  • Metal has a higher specific heat capacity
  • Metal conducts thermal energy away from the hand faster
  • Wood radiates more energy than metal

4 Short Answer Questions

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